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Master-Level Programming Assignment Example 1: Data Structures in Python
Question:
Write a Python program to implement a Least Recently Used (LRU) Cache. The cache should:
- Be initialized with a fixed capacity.
- Store key-value pairs.
- Remove the least recently used item when the cache exceeds its capacity.
Solution:
from collections import OrderedDict
class LRUCache:
def __init__(self, capacity):
self.cache = OrderedDict()
self.capacity = capacity
def get(self, key):
if key not in self.cache:
return -1
else:
# Move accessed key to the end
self.cache.move_to_end(key)
return self.cache[key]
def put(self, key, value):
if key in self.cache:
# Move the existing key to the end
self.cache.move_to_end(key)
elif len(self.cache) = self.capacity:
# Remove the first item (least recently used)
self.cache.popitem(last=False)
self.cache[key] = value
# Example Usage
lru = LRUCache(3)
lru.put(1, "A")
lru.put(2, "B")
lru.put(3, "C")
print(lru.get(1)) # Output: A
lru.put(4, "D") # Removes key 2 (least recently used)
print(lru.get(2)) # Output: -1Explanation:
This solution utilizes Python's OrderedDict to manage the LRU cache. The get method retrieves a value by its key while maintaining its "recently used" status, and the put method ensures efficient key-value insertion and eviction based on cache capacity.
With expert guidance, implementing such fundamental data structures becomes intuitive, fostering a deeper understanding of algorithms and system design.
Master-Level Programming Assignment Example 2: Algorithm Optimization in Java
Question:
Write a Java program to solve the following problem:
Given an array of integers, find all unique triplets in the array that sum up to zero.
Solution:
import java.util.*;
public class ThreeSum {
public ListListInteger findTriplets(int[] nums) {
ListListInteger result = new ArrayList();
Arrays.sort(nums); // Sort the array
for (int i = 0; i nums.length - 2; i++) {
if (i 0 nums[i] == nums[i - 1]) continue; // Avoid duplicates
int left = i + 1, right = nums.length - 1;
while (left right) {
int sum = nums[i] + nums[left] + nums[right];
if (sum == 0) {
result.add(Arrays.asList(nums[i], nums[left], nums[right]));
left++;
right--;
// Skip duplicates
while (left right nums[left] == nums[left - 1]) left++;
while (left right nums[right] == nums[right + 1]) right--;
} else if (sum 0) {
left++;
} else {
right--;
}
}
}
return result;
}
public static void main(String[] args) {
ThreeSum solution = new ThreeSum();
int[] nums = {-1, 0, 1, 2, -1, -4};
System.out.println(solution.findTriplets(nums));
}
}
Explanation:
This program efficiently solves the "three-sum" problem using a combination of sorting and two-pointer techniques. Sorting simplifies the problem by enabling efficient traversal, while the two-pointer approach reduces computational complexity. The use of checks ensures duplicate triplets are avoided.
Assignments like this enhance problem-solving skills by challenging students to think critically about algorithm efficiency and memory optimization.
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Leveraging Assignment Solutions to Learn
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Final Thoughts
Programming assignments may seem daunting at first, but with the right guidance and resources, they become manageable and even enjoyable. At ProgrammingHomeworkHelp.com, we’re committed to providing exceptional programming assignment help that empowers students to achieve their academic goals.
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